-8p^2-12p+8=0

Solution for -8p^2-12p+8=0 equation:

-8p^2-12p+8=0

a = -8; b = -12; c = +8;
Δ = b2-4ac
Δ = -122-4·(-8)·8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-20}{2*-8}=\frac{-8}{-16}
=1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+20}{2*-8}=\frac{32}{-16}
=-2
$